The Henderson Inverse Theorem
The Henderson Inverse Theorem is an important result on the relationship between the radial distribution function and pairwise additive potential in a statistical ensemble. This theorem is the basis for the structure-optimized potential refinement algorithm and provides a variational solution to the statistical mechanical inverse problem.
We first need to establish the Gibbs and Gibbs-Bogoliubov inequalities for a quantum system. The Gibbs inequality is an important result about the information entropy of a system while the Gibbs-Bogoliubov inequality establishes an important relationship between the free energy and entropy in the canonical ensemble.
The Gibbs Inequality
Proof: Let $\rho_1$ and $\rho_2$ be positive, trace-class, and linear density operators on a Hilbert space, $H$, such that $Tr(\rho_i) = 1$. Then we can express the states $\rho_1$ and $\rho_2$ in an arbitrary basis of $H$ such that,
$$ \rho_1 = \sum_\alpha p_\alpha \ket{\alpha} \bra{\alpha} $$
$$ \rho_2 = \sum_\alpha q_\alpha \ket{\alpha} \bra{\alpha} $$
We then compute the difference between the cross entropy, $\rho_1 \log (\rho_2)$, and information entropy of $\rho_1$, $\rho_1 \log (\rho_1)$,
$$ \rho_1 \log (\rho_2) - \rho_1 \log (\rho_1) = \sum_{\alpha,\beta} [p_\alpha \ket{\alpha} \bra{\alpha} \log (q_\beta) \ket{\beta} \bra{\beta} - p_\alpha \ket{\alpha} \bra{\alpha} \log (p_\beta) \ket{\beta} \bra{\beta}] $$
and since ${\alpha}$ and ${\beta}$ are orthonormal bases,
$$ = \sum_{\alpha} [p_\alpha \log (q_\alpha) - p_\alpha \log (p_\alpha)]\ket{\alpha} \bra{\alpha} $$
Taking the trace of this operator we obtain,
$$ Tr(\rho_1 \log (\rho_2) - \rho_1 \log (\rho_1)) = \sum_{\alpha} [p_\alpha \log (q_\alpha) - p_\alpha \log (p_\alpha)] = \sum_{\alpha} p_\alpha \log \frac{q_\alpha}{p_\alpha} $$
Note that since $\log x \leq x - 1$,
$$ \sum_{\alpha} p_\alpha \log \frac{q_\alpha}{p_\alpha} \leq \sum_{\alpha} [q_\alpha - p_\alpha] = 0 $$
and finally, since the trace is a linear operator, this means that,
$$ Tr(\rho_1 \log (\rho_2)) \leq Tr(\rho_1 \log (\rho_1)) $$
The Gibbs-Bogoliubov Inequality
Proof: Suppose we take the state $\rho_2$ in the canonical ensemble so that,
$$ \rho_2 = \exp(-\beta \mathcal{H_2}) / Z $$
where $\beta$ is the inverse thermal energy, $\mathcal{H_2}$ is the Hamiltonian, and $Z$ is the partition function. Then for some $\rho_1$ we have,
$$ Tr(\rho_1 (-\beta \mathcal{H_2} - \log Z)) \leq Tr(\rho_1 \log (\rho_1)) = - S_1 / k_B $$
where $S_1 = -k_B Tr(\rho_1 \log (\rho_1))$ is the entropy of system 1 and $k_B$ is the Boltzmann constant. Since the trace is a linear operator, we can separate the argument of the trace on the left hand side and divide both sides by the thermodynamic $\beta$ to obtain,
$$ Tr(\rho_1\mathcal{H_2}) + k_BT \log Tr(Z) \geq + T S_1 $$
But $Tr(\rho_1\mathcal{H_2})$ is just the expectation of $\mathcal{H_2}$ over system state 1 and $-k_BT \log Tr(Z)$ is the definition of the Helmholtz free energy in the Canonical ensemble. Thus,
$$ F_2 \leq \langle \mathcal{H_2} \rangle_1 - T S_1 $$
For system 1,
$$ F_1 \leq \langle \mathcal{H_1} \rangle_1 - T S_1 $$
Combining the two expressions gives us the Gibbs-Bogoliubov inequality,
$$ F_2 \leq F_1 + \langle \mathcal{H_2} - \mathcal{H_1} \rangle_1 $$
The Henderson Inverse Theorem
The content of the Henderson Inverse Theorem is as follows: Two systems with Hamiltonians of the form,
$$ \mathcal{H} = \sum_i \frac{p_i^2}{2m} + \frac{1}{2} \sum_{i \neq j} u(|\mathbf{r_i} - \mathbf{r_j}|) $$
with the same radial distribution function, $g^{(2)}(\mathbf{r_i},\mathbf{r_j})$,
$$ g^{(2)}(\mathbf{r_i},\mathbf{r_j}) = \frac{1}{\rho^2}\bigg\langle \sum_i \sum_j \delta(\mathbf{r} - \mathbf{r_i}) \delta(\mathbf{r}’ - \mathbf{r_j}) \bigg\rangle $$
have pair potentials, $u(|\mathbf{r_i} - \mathbf{r_j}|)$, that differ by at most a trivial constant.
Proof: Suppose that two systems with a pairwise additive Hamiltonian have equal radial distribution functions and $u_1 - u_2 \neq c$ where $c$ is some constant. Then,
$$ \langle \mathcal{H_2} - \mathcal{H_1} \rangle_1 \neq c $$
and since the Helmholtz free energies are constants,
$$ F_2 - F_1 < \langle \mathcal{H_2} - \mathcal{H_1} \rangle_1 $$
where we lose the possibility of equality from the Gibbs-Bogoliubov inequality. Now, we can expand the expectation of the Hamiltonian in terms of the radial distribution function (since the system is pairwise additive) so that,
$$ F_2 - F_1 < \frac{n}{2} \int [u_2 - u_1] g_1(\mathbf{r}) d^3\mathbf{r} $$
and the same holds for a swap of the indices,
$$ F_1 - F_2 < \frac{n}{2} \int [u_1 - u_2] g_2(\mathbf{r}) d^3\mathbf{r} $$
Combining these two equations gives,
$$ 0 < 0 $$
a contradiction. Therefore, our premise that the radial distribution functions are equal while the pairwise additive potential energies differ by a trivial constant must be false. The only other possible difference between the potential energies is constant, so this must be true to satisfy the Gibbs-Bogoliubov inequality.
The Henderson Inverse Theorem is a valuable tool to predict this unique (up to a constant) potential energy function from the radial distribution function of a fluid. It is often employed in coarse-grained models under the name of iterative Boltzmann inversion (IBI) and in experimental data with empirical potential structure refinement (EPSR) or structure-optimized potential refinement (SOPR) [1].
[1] Brennon L. Shanks, Jeffrey J. Potoff, and Michael P. Hoepfner The Journal of Physical Chemistry Letters 2022 13 (49), 11512-11520 DOI: 10.1021/acs.jpclett.2c03163